Leave a Comment / Linear Algebra, Practice Questions / By Rsquared Mathematics Linear Algebra MCQs and MSQs with Solutions for CSIR NET, IIT JAMSystem of Equations – I Practice Questions for NET JRF Linear Algebra <br> Assignment: System of Equations 1. The row space of a \(20 \times 50\) matrix \(A\) has dimension 13. What is the dimension of the space of solutions of \(A x=0\)? (a.) 7 (b.) 13 (c.) 33 (d.) 37 Explanation for Question 1: Let \(T\) be the linear transformation corresponding to \(A\), say \(T: \mathbb{F}^{50} \rightarrow \mathbb{F}^{20}\) has rank 13. Then by the rank nullity theorem, \[ n(T)=37 \] This completes the explanation for Question 1. Submit 2. Let \(A\) be an \(m \times n\) matrix of rank \(n\) with real entries. Choose the correct statement. (a.) \(A x=b\) has a solution for any \(b\). (b.) \(A x=0\) does not have a solution. (c.) If \(A x=b\) has a solution, then it is unique. (d.) \(y^{\prime} A=0\) for some nonzero \(y\), where \(y^{\prime}\) denotes the transpose of the vector \(y\). Explanation for Question 2: Note that the corresponding linear transformation to \(A\) is one-one as it has a full column rank. Thus, if a solution exists, then it is unique. This completes the explanation for Question 2. Submit 3. Which of the following matrices has the same row space as the matrix \(\left(\begin{array}{lll}4 & 8 & 4 \\ 3 & 6 & 1 \\ 2 & 4 & 0\end{array}\right)\)? (a.) \(\left(\begin{array}{lll}1 & 2 & 0 \\ 0 & 0 & 1 \end{array}\right)\) (b.) \(\left(\begin{array}{lll}1 & 1 & 0 \\ 0 & 0 & 1 \end{array}\right)\) (c.) \(\left(\begin{array}{lll}0 & 1 & 0 \\ 0 & 0 & 1 \end{array}\right)\) (d.) \(\left(\begin{array}{lll}1 & 0 & 0 \\ 0 & 1 & 0 \end{array}\right)\) Explanation for Question 3: \[ \begin{aligned} A=\left[\begin{array}{lll} 4 & 8 & 4 \\ 3 & 6 & 1 \\ 2 & 4 & 0 \end{array}\right] & \sim\left[\begin{array}{lll} 4 & 8 & 4 \\ 3 & 6 & 1 \\ 1 & 2 & 0 \end{array}\right] \sim\left[\begin{array}{lll} 0 & 0 & 4 \\ 0 & 0 & 1 \\ 1 & 2 & 0 \end{array}\right] \\ & \sim\left[\begin{array}{lll} 0 & 0 & 1 \\ 0 & 0 & 1 \\ 1 & 2 & 0 \end{array}\right] \end{aligned} \] This completes the explanation for Question 3. Submit 4. The determinant of the \(n \times n\) permutation matrix \(\begin{pmatrix} & & & & & 1 \\ & & & & 1 & \\ & & & \cdot & & \\ & & \cdot & & & \\ & 1 & & & & \\ 1 & & & & & \end{pmatrix}\) is (a.) \((-1)^n\) (b.) \((-1)^{\left\lceil\frac{n}{2}\right\rceil}\) (c.) -1 (d.) 1 Explanation for Question 4: For \(n=1, |A|=1 \Rightarrow a, c\) are false. For \(n=2, |A|=-1 \Rightarrow d\) is false. This completes the explanation for Question 4. Submit 5. The determinant \(\left|\begin{array}{lll}1 & 1+x & 1+x+x^{2} \\ 1 & 1+y & 1+y+y^{2} \\ 1 & 1+z & 1+z+z^{2}\end{array}\right|\) is equal to (a.) \((z-y)(z-x)(y-x)\) (b.) \((x-y)(x-z)(y-z)\) (c.) \((x-y)^{2}(y-z)^{2}(z-x)^{2}\) (d.) \(\left(x^{2}-y^{2}\right)\left(y^{2}-z^{2}\right)\left(z^{2}-x^{2}\right)\) Explanation for Question 5: \[ \begin{aligned} & =z^2 y-y^2 z+x y^2-x y z-x z^2+x^2 z-y x^2+x y z \\ & =y\left(z^2-y^0 z+x y-x_2\right)-x\left(z^2+y x-x^2 z-y^2\right) \\ & =\Rightarrow(y-x)\left(z^2-y z+x y-x z\right) \\ & =(y-x)(z-x) \lg 2)(z-y) \\ & \end{aligned} \] This completes the explanation for Question 5. Submit 6. Let \(A\) be a \(3 \times 4\) matrix and \(b\) a \(3 \times 1\) matrix with integer entries. Suppose that the system \(A x=b\) has a complex solution then (a.) \(A x=b\) has an integer solution. (b.) \(A x=b\) has a rational solution. (c.) The set of real solutions to \(A x=0\) has a basis consisting of rational solutions. (d.) If \(b \neq 0\) then \(A\) has positive rank. Explanation for Question 6: Note that the system is consistent and entries in \(A\) are integers implying that the solution is rational but need not be an integer. Also, if \(b\) is non-zero then matrix \(A\) must be non-zero, hence the options b, c, and d are correct. This completes the explanation for Question 6. Submit 7. The matrix \(A=\begin{pmatrix} 5 & 9 & 8 \\ 1 & 8 & 2 \\ 9 & 1 & 0 \end{pmatrix}\) satisfies: (a.) \(A\) is invertible and the inverse has all integer entries. (b.) Det\((A)\) is odd. (c.) Det\((A)\) is divisible by 13. (d.) Det\((A)\) has at least two prime divisors. Explanation for Question 7: \(|A|=-416=-13 \times 32\) \(A^{-1}\) does not have integer entries as there are entries in \(adj(A)\) which are not divisible by 13. This completes the explanation for Question 7. Submit 8. Let \(A\) be a \(4 \times 7\) real matrix and \(B\) be a \(7 \times 4\) real matrix such that \(A B=I_{4}\) where \(I_{4}\) is the \(4 \times 4\) identity matrix. Which of the following is/are always true? (a.) Rank\((A)=4\). (b.) Rank\((B^{\prime})=7\). (c.) Nullity\((B)=0\). (d.) \(B A=I_{7}\) where \(I_{7}\) is the \(7 \times 7\) identity matrix. Explanation for Question 8: As the rank of \(AB\) is 4, it implies that the rank of \(A\) and \(B\) is at least 4. Let the linear transformations corresponding to \(A\) be \(T_A: \mathbb{R}^{7} \rightarrow \mathbb{R}^{4}\). Thus, using the rank-nullity theorem, the rank of \(A\) can be at most 4. Combining together, the rank of \(A\) must be 4. Let the linear transformations corresponding to \(B\) be \(T_B: \mathbb{R}^{4} \rightarrow \mathbb{R}^{7}.\) Note that the rank of \(B\) is almost 4. Thus, the rank of \(B\) is also 4 and \(T_B\) is a one-one linear transformation. Hence the nullity of \(B\) is \(0\). This completes the explanation for Question 8. Submit 9. For the matrix \(A\) as given below, which of them satisfy \(A^6=I\)? (a.) \(A=\begin{pmatrix} \cos\frac{\pi}{4} & \sin\frac{\pi}{4} & 0 \\ -\sin\frac{\pi}{4} & \cos\frac{\pi}{4} & 0 \\ 0 & 0 & 1 \end{pmatrix}\) (b.) \(A=\begin{pmatrix} 1 & 0 & 0 \\ 0 & \cos\frac{\pi}{3} & \sin\frac{\pi}{3} \\ 0 & -\sin\frac{\pi}{3} & \cos\frac{\pi}{3} \end{pmatrix}\) (c.) \(A=\begin{pmatrix} \cos\frac{\pi}{6} & 0 & \sin\frac{\pi}{6} \\ 0 & 1 & 0 \\ -\sin\frac{\pi}{6} & 0 & \cos\frac{\pi}{6} \end{pmatrix}\) (d.) \(A=\begin{pmatrix} \cos\frac{\pi}{2} & \sin\frac{\pi}{2} & 0 \\ -\sin\frac{\pi}{2} & \cos\frac{\pi}{2} & 0 \\ 0 & 0 & 1 \end{pmatrix}\) Explanation for Question 9: All matrices are rotation matrices \(A^6=I \Rightarrow\) Angle of rotation can be \(\frac{2 \pi}{6}, \frac{2 \pi}{3}, \frac{2 \pi}{2}\) \(\Rightarrow a, c, d\) are false. This completes the explanation for Question 9. Submit 10. Consider a homogeneous system of linear equations \(A x=0\) where \(A\) is an \(m \times n\) real matrix and \(n>m\). Which of the following statements are always true? (a.) \(A x=0\) has a solution. (b.) \(A x=0\) has no nonzero solution. (c.) \(A x=0\) has a nonzero solution. (d.) Dimension of the space of all solutions is at least \(n-m\). Explanation for Question 10: Linear transformation corresponding to \(A\), say \(T: \mathbb{R}^n \longrightarrow \mathbb{R}^m\) s.t. \(m < n\) . Using the rank-nullity theorem, \[ \begin{gathered} \eta(T)>0 \\ \Rightarrow \operatorname{Ker}(T) \neq\{0\} \end{gathered} \] \(\Rightarrow A x=0\) has a nonzero solution and the nullity of \(T\) is at least \(n-m\). This completes the explanation for Question 10. Submit Leave a Comment Cancel ReplyYour email address will not be published. Required fields are marked *Type here..Name* Email* Website Save my name, email, and website in this browser for the next time I comment.
Practice Questions for NET JRF Linear Algebra : Vector Space and Subspaces – I Practice Questions | By Rsquared Mathematics | Linear Algebra, Vector Space and Subspaces
Practice Questions for NET JRF Linear Algebra : Vector Space and Subspaces – II Practice Questions, Linear Algebra | By Rsquared Mathematics | Linear Algebra, Vector Space and Subspaces